Your formulas give the coordinates of the projection of a point onto the plane on the Greenwich meridian (longitude = 0). (1) A distance of 10 meters is *very* small compared to the radius of the earth, so we can definitely use a flat-earth approximation. I'll respond to each of your questions after stating the question: We’ll be focusing on a particular projection that is appropriate for short-range distance calculations, rather than dealing with what his existing map might be.ĭoctor Rick answered: Hi, Hing. Hing is apparently thinking that transforming coordinates on earth to \((x,y)\) coordinates on a map will allow reasonably accurate distance calculations on the map that’s true, but the reality is that there are different map “projections” that might be used on his map, and his formula is not appropriate for a map anyway. I would like to know how to compute the (x,y) of a particular point in the map. I have a digital map giving the four corners in terms of longitudes and latitudes, say, (a1,b1), (a1,b2), (a2,b1), (a2,b2). The distance is calculated as the square root of (x1-x2)^2+(y1-y2)^2. I converted the (a,b) to (x,y) using the following formulae: Given 2 positions in terms of longitude and latitude, say, (a1, b1) and (a2,b2) with the distance between them very small, say, within 10 meters, I would like to know if there are any methods that can compute their separation with the best accuracy. I have two questions on the transformation between (x,y) and (longitude, latitude).ġ. The first question is from 2002: Transformation between (x,y) and (longitude, latitude) This is a “flat-earth approximation” to distance. We’ve looked at two formulas for the distance between points given their latitude and longitude here we’ll examine one more formula, which is valid only for small distances.
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